<u>Part 1</u>
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We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is 
<u>Part 2</u>
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We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,
Thus, the domain in interval notation is 
Answer:
B
Step-by-step explanation:
Answer:
1. 3a2
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
√(2x − 1) + 2 = x
√(2x − 1) = x − 2
2x − 1 = (x − 2)²
2x − 1 = x² − 4x + 4
0 = x² − 6x + 5
0 = (x − 1) (x − 5)
x = 1 or 5
Check for extraneous solutions.
√(2(1) − 1) + 2 = 1
√(1) + 2 = 1
3 = 1
No solution
√(2(5) − 1) + 2 = 5
√(9) + 2 = 5
5 = 5
x = 5
