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3 years ago

Please help me with this question

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

5 0

Multiply those numbers

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Help me solve this problem please

mel-nik [20]

It’s only a vertical angle

7 0

2 years ago

Which equation is part of solving the system by substitution? 4(y + 11)2 – 3y2 = 8 4(11 – y)2 – 3y2 = 8 4(y – 11)2 – 3y2 = 8 4(–

swat32

Answer:

$4(11-y)^{2} -3y^{2}=8$

Step-by-step explanation:

we have

$x+y=11$ ----> equation A

$4x^{2} -3y^{2}=8$ ----> equation B

Solve the system by substitution

step 1

isolate the variable x in the equation A

$x=11-y$ ----> equation A1

step 2

Substitute the equation A1 in the equation B

$4(11-y)^{2} -3y^{2}=8$

Solve for y

3 0

3 years ago

Read 2 more answers

Find the solutions of the quadratic equation 14x^2+9x+10=014x

Vesnalui [34]

Answer:

Option B. $x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$14x^{2}+9x+10=0$

$a=14\\b=9\\c=10$

substitute in the formula

$x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}$

$x=\frac{-9(+/-)\sqrt{-479}} {28}$

Remember that

$i=\sqrt{-1}$

substitute

$x=\frac{-9(+/-)\sqrt{479}i} {28}$

$x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

5 0

3 years ago

(a) At Smith's Bike Rentals, it costs $18 to rent a bike for 4 hours.

bagirrra123 [75]

$4.50 you just do 18/4 to get ur answer per hour

8 0

3 years ago

Read 2 more answers

Find all solutions and solutions in interval[0,2pi)

frutty [35]

$\bf sin(2\theta)=2sin(\theta)cos(\theta)\\\\
-------------------------------\\\\
sin(2x)-\sqrt{3}cos(x)=0\implies 2sin(x)cos(x)-cos(x)\sqrt{3}=0
\\\\\\
\stackrel{\stackrel{common}{factor}}{cos(x)}[2sin(x)-\sqrt{3}]=0\\\\
-------------------------------\\\\$

$\bf cos(x)=0\implies \measuredangle x=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------\\\\
2sin(x)-\sqrt{3}=0\implies 2sin(x)=\sqrt{3}\implies sin(x)=\cfrac{\sqrt{3}}{2}
\\\\\\
\measuredangle x=
\begin{cases}
\frac{\pi }{3}\\\\ \frac{2\pi }{3}
\end{cases}$

7 0

3 years ago