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JulijaS [17]
2 years ago
13

What is

4}{6} = \frac{b}{2}" alt="\frac{b-4}{6} = \frac{b}{2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Gala2k [10]2 years ago
5 0

Answer:

b = -2

Step-by-step explanation:

1) Cross multiply the proportion, in turn, you receive 2(b-4) = 6b.

2) Simply said equation, you should have 2b - 8 = 6b.

3) Subtract the 2b from each side, effectively canceling it out on the left (original position) and resulting in 6b to become 4b (6b - 2b = 4b).

4) After you have -8 = 4b, you can divide both sides by 4, canceling out on the right (original position).

5) You are finally left with -2 = b, reversing this results in b = -2.

-2 is your answer.

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What is the slope of a line perpendicular to the line whose equation is 6x+4y=-56
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Answer:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.Step-by-step explanation:

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5 0
2 years ago
Complete the steps to find all zeroes of the function f(x) = x4 − 4x3 − 4x2 + 36x − 45. This function has roots.
xxTIMURxx [149]
Steps?

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  (x-2)² +1
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7 0
3 years ago
Read 2 more answers
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0
3 years ago
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