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3 years ago

9

Cecilia packed a fruit basket for her new neighbors. If 20% of 30 pieces of fruit were bananas, what fraction of the fruit were

bananas? Help!

2 answers:

Sholpan [36]3 years ago

8 0

6/30 or if you want it in simplest form it would be 1/5

Anettt [7]3 years ago

7 0

Answer:

6/30

Step-by-step explanation:

20 percent of 30 is 6 ^_^

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Find the value of <br> x<br> x<br> that makes the expressions equivalent.<br> 2(x+9); 30+18

Vlada [557]

Answer:

$x=15$

Step-by-step explanation:

We are given the equations $2(x+9), 30+18$ to search for a value of $x$ that yields an equivalent statement. $2(x+9)=30+18\\2(x+9)=48\\x+9=24\\x=15$ .

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2 years ago

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Neal used magnetic letters to spell the word communication on his file cabinet. One of the magnets fell on the floor. What is th

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the likehood that an n fell on the floor is 2 in 13.

Step-by-step explanation:

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3 years ago

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One bag of mulch covers a 1 3/4 yard section of Hailey's garden. If her garden is 10 3/5 yards in size, how many bags of mulch d

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7 bag of mulch cover will be needed for Hailey's garden.

Step-by-step explanation:

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2 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

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3 years ago

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ludmilkaskok [199]

The volume is 336 cubic feet

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144+192=336

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2 years ago

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