You buy 5 balloons and 3 banners for $14. Your friend buys 1 balloon and
1 answer:
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14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.
To solve this problem, we would write a system of linear equations.
- Let x represent the machine that cost $150
- Let y represent the machine that cost $225
We can proceed to write our equations now.
From equation 1
put equation (iii) into (ii)
Since we know the number of y, we can simply substitute it into equation (i) and solve.
From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.
Learn more about system of equations here;
Answer:
Step-by-step explanation:
In a deck of cart, we have:
a = 4 (aces)
t = 4 (three)
j = 4 (jacks)
And the total number of cards in the deck is
n = 52
So, the probability of drawing an ace as first cart is:
At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is
Therefore, the probability of drawing a three at the 2nd draw is
Then, at the third draw, the previous 2 cards are not replaced, so there are now
cards in the deck. So, the probability of drawing a jack is
Therefore, the total probability of drawing an ace, a three and then a jack is: