I am assuming 10 and 12 are the legs and 23 is the hypotenuse?
With that said, we can use the pythagorean theorem a^2+b^2=c^2
a^2+b^2=c^2 = Right triangle
a^2+b^2 < c^2 = abtuse
a^2+b^2 > c^2 = acute
10^2 + 12^2 = 23^2
244 = 529
244 < 529
It is abtuse
2.4⋅(−3.4)⋅(−1.25)=−3.4⋅2.4⋅(−1.25) 2.4⋅(−3.4)⋅(−1.25)=−3.4⋅2.4⋅(−1.25) (42⋅3.5)+(42⋅1.3)+(42⋅5.2)=42⋅(3.5+1.3+5.2) (42⋅3.5)+(42⋅1.3)+(42⋅5.2)=42⋅(3.5+1.3+5.2) −2.5⋅(4⋅3.67)=(−2.5⋅4)⋅3.67 −2.5⋅(4⋅3.67)=(−2.5⋅4)⋅3.67 −3⋅(6.48)=(−3⋅6)+(−3⋅0.4)+(−3⋅0.08) −3⋅(6.48)=(−3⋅6)+(−3⋅0.4)+(−3⋅0.08) All of them
Answer:
8 X 10^(9)
Step-by-step explanation:
Originally we have 10 digit phone numbers excluding the area code.
For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)
But if we exclude 1 and 0 for the first digit, we are left with 8 digits.
8P1 X .......
In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.
8P1 X 10P1 X 10P1 X...
Adding the area code while assuming 10P1 is just 10...we get:
1 X 1 X 1 X 8 X 10^(9)
= 8000000000
Very interesting question, thanks for the opportunity!
C and D are the same, so its between A and B, which concludes your answer should be B
Answer:
Step-by-step explanation:
<u>Triangles And Circles</u>
If a right triangle is inscribed in a circle (or the circle is circumscribed around the right triangle), then the hypotenuse of the triangle is the diameter of the circle.
The right triangle has both legs of known lengths, thus the hypotenuse (the diameter of the circle is):
Since 50=2*25:
Thus the radius of the circle is: