Answer:
A macromolecule is a very large molecule, such as protein, commonly created by the polymerization of smaller subunits (monomers). ... The most common macromolecules in biochemistry are biopolymers (nucleic acids, proteins, carbohydrates and lipids) and large non-polymeric molecules (such as lipids and macrocycles).
Explanation:
<span>UN1825 refers to Sodium monoxide.It is a white granular material. It reacts with water to give sodium hydroxide with the evolution of heat. It is corrosive to metals and tissue. The oxides of sodium and potassium react with water vigorously and with enough evolution of heat to cause boiling and spattering of hot caustic solution.Reaction with water may generate much heat that will increase the concentration of fumes in the air. Fire will produce irritating, corrosive and/or toxic gases. Runoff from fire control or dilution water may be corrosive and/or toxic and cause pollution.</span>
I believe (not sure) that the answer is B, viruses must invade their host before being able to reproduce.
I remember seeing a diagram of the general life of a virus, and I remember seeing the virus sticking to a cell, merging in, and reproducing thereafter (sort of like a factory). Once again, I am not sure and the answer may as well be another one.
To be perfectly honest, I'm not sure what problem 32 is asking. It seems like there's set up to a question, but the actual question itself is missing.
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For problem 33, we divide the tape's distance by its time. I'm assuming that problem 33 is using the set up info from problem 32.
Recall that
distance = rate*time
we can rearrange things to say
rate = distance/time
So that's why we divide distance over time. The tape's length is effectively the distance, more or less. Imagine that one marker on the tape travels from one end of the reel to the other. It would have to travel the length of the tape when the full tape duration elapses.
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So,
rate = distance/time
rate = (260 meters)/(180 seconds)
rate = (260/180) meters per second
rate = 1.44 meters per second, which is approximate
I'm rounding to 3 sig figs.
Answer:
Let's consider that red fruit is dominant over the yellow fruit.
<em>The phenotype of the red fruit of P1 will be red fruit and the genotype will be RR.</em>
<em>The phenotype of the yellow fruit of P1 will be yellow fruit and the genotype will be rr.</em>
To check the outcomes of the F1 generation, lets cross the P1 generation:
r r
R Rr Rr
R Rr Rr
<em>The results show that all the offsprings from the F1 generation will show the dominant phenotype which is red fruit and they will have Rr genotype. </em>
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