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KIM [24]
2 years ago
15

10. The perimeter of the rectangle below is 30 inches. Find the value of x. 5x X-3

Mathematics
1 answer:
Zigmanuir [339]2 years ago
4 0
The answer is 3. This is because the perimeter is 30 so 5x+5x+x-3+x-3 = 30. Thus you have 12x-6=30 so x = 3
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150 seconds is >, <, or = 3 minutes
kap26 [50]

Answer:

150 seconds< 3 minutes

Step-by-step explanation:

a minute is 60 seconds; 60×3 =180

180 seconds is greater than 150 seconds

4 0
3 years ago
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Write an equivalent expression for x^4 over 4<br><br> help <br> please
ioda

Answer:

1/4 · x⁴

Step-by-step explanation:

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2 years ago
PLEASE HELP ME WITH THIS THANKS
stich3 [128]

Answer:

The answer to your question is Volume = 12735.06 cm³

Step-by-step explanation:

Data

a = 11.26 cm

s = 13 cm

h = 29 cm

Formula

V = BH

Process

1.- Calculate the area of the base

Area = B = Pa/2

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        = 878.28/2

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2.- Calculate the volume

Volume = BH

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3 years ago
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6 to the second power ÷ [(4.3×3)+5.1]
Black_prince [1.1K]
2 is the answer
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2 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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