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SashulF [63]
3 years ago
6

I need help w this problem please help

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

I'm pretty sure it is C.. that's the way I learned it.. you change the signs opposite

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Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.
kogti [31]
Answer: 
x = 2

2x + 1 = -x +7           Add and subtract 
3x = 6                                divide
x = 2
3 0
3 years ago
How to solve the inequality 1/5 ≤ x/15?
MAXImum [283]

Answer:

3 <_ x

Step-by-step explanation:

multiply both sides by 15

1/5 * 15 <_ x

15/5 <_ x

3 <_ x

8 0
3 years ago
ONE GEOMETRY QUESTION
kondor19780726 [428]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Solve for q. Write your answer as “q=___”
wolverine [178]

Answer:

7q-46= 3q +6

7q-3q = 6+ 46

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3 0
3 years ago
Read 2 more answers
Bad gums may mean a bad heart. Researchers discovered that 82% of people who have suffered a heart attack had periodontal diseas
saveliy_v [14]

Answer:

37.27% probability that he or she will have a heart attack.

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Periodontal disease

Event B: Heart attack

Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums.

This means that P(A|B) = 0.82

Only 33% of healthy people have this disease.

This means that P(A) = 0.33

Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.

This means that P(B) = 0.15

If someone has periodontal disease, what is the probability that he or she will have a heart attack

P(B|A) = \frac{0.15*0.82}{0.33} = 0.3727

37.27% probability that he or she will have a heart attack.

6 0
3 years ago
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