Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Step-by-step explanation:
0x<3
x>3/0
x>∞
x is undefined.
The Answer Is 14/15 Hope This Helps.
Answer: Log9,(11/7)^4
Step-by-step explanation:
according to the rules of logarithm
1)Subtraction sign(-) becomes division(÷),while addition(+)becomes multiplication (x)
2) the number in front of the log figure becomes an indices