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rewona [7]
3 years ago
7

Error Analysis Find (4) (-5) (-3) . Use pencil and paper. Describe an error you could make that results in the opposite of the c

orrect product. nothing
Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0

Answer:

He didn’t do his math right

Step-by-step explanation:

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Solve the equation 30=-5(m+6)+m
notka56 [123]
30 = -5(m+6) + m
30 = -5m - 30 + m 
0 = -4m
0 = m
6 0
3 years ago
Round 793,907 to the nearest 100,000
olasank [31]
800,000 is the correct answer

6 0
3 years ago
Can someone please help me and explain? please
mariarad [96]
Composite figure is made up of 4 triangles and a square.

Area of Square = Length x Length 
Area of Square = 12 x 12
Area of Square= 144 cm²

Area of triangle = 1/2 x base x height
Area of triangle  = 1/2 x 12 x 8 
Area of triangle  = 48 cm²

Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²

Total Area = 144 + 192 = 336 cm² 

\Longrightarrow \boxed { \boxed { Answer : 336 cm^{2} }}


4 0
3 years ago
Find the distance between the points (2,4) and (6,1).
balu736 [363]

Answer:

1

Step-by-step explanation:2 and 6 are the first ones in each set so 6-2 is 4.4 and 1 are the second ones in each set 1-4 is -3 4+-3 is 1.

4 0
3 years ago
1) The deer population in a national park is expected to decline over time. The park
Lorico [155]

Answer:

Here's what I find.

Step-by-step explanation:

You have 800 deer at the end of Year 1, and you expect the population to decrease each year thereafter.

a) i) The recursive formula

Let dₙ = the deer population n years after the initial measurement.

d_{n} = d_{n - 1}r^{n}

For this situation,

d_{n} = d_{n - 1}(0.5)^{n}

a) ii) Definitions

n = the number of years from first measurement

r = the common ratio, that is, the deer population at the end of one year divided by the population of the previous year.

a) iii) First term of sequence

The first term of the sequence is d₀, the population when first measured.

b) The function formula

The formula for the nth term of a geometric series is

d_{n} =d_{0}r^{n - 1}

c) Value of d₀

Let n = 2; then d₂ = 800

\begin{array}{rcl}800 & = & d_{0}(0.5)^{2 - 1}\\800 & = & d_{0}(0.5)\\\\d_{0} & = & \dfrac{800}{0.5}\\\\& =&\mathbf{1600}\\\end{array}

4 0
3 years ago
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