Ask question

Ask question

All categories

3 years ago

10

Right ∆ABC has coordinates A(-7, 3), B( -7, 10), and C(-1, 3). The triangle is reflected over the x - axis and then reflected ag

ain over the y - axis to create ∆A'B'C'. Which are the coordinates of vertex A'?

2 answers:

Mrrafil [7]3 years ago

7 0

Vertex A’ would be (7, -3)

geniusboy [140]3 years ago

7 0

Answer:

7,3

Step-by-step explanation:

You might be interested in

(7+4)6 =<br> Step by step is 42+24=66

ddd [48]

Answer:

66

Step-by-step explanation:

Add what is in the parenthesis, in this case 7+4:

(7+4)

=11

Multiply 11 by 6:

(11)6

=66

hope this helps :)

5 0

3 years ago

Read 2 more answers

What is 1,988 divided by5

labwork [276]

Answer:

397.6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I-ready test 7th grade

snow_lady [41]

Answer:

A

Step-by-step explanation:

3 0

3 years ago

Answer 1/5d + 1/8d=2

klemol [59]

$\frac{1}{5}d+\frac{1}{8}d=2\\\\
Make\ common\ denominator\ of\ \frac{1}{5}\ and\ \frac{1}{8}\ which\ is\ 40:\\\\
\frac{8}{40}d+\frac{5}{40}d=2\ \ \ |*40\\\\8d+5d=2*40\\\\
13d=80\ \ |:13\\\\d=\frac{80}{13}=6\frac{2}{13}\\\\
Answer\ is\ d=6\frac{2}{13}.$

7 0

3 years ago

Read 2 more answers

With out computing each sum find which is greater O or E and how much O=5+7+9+11...+101

nikitadnepr [17]

I think that O would be greater because the last numbers listed are 100 and 101 and O has the ending value of 101, which is greater than 100, so it only makes sense that O would be a greater number than E.

Hope this helps! ;)

4 0

3 years ago