In a school day each student has to participate either in music or sport . Out of 350 students of the school 250 participated in
1 answer:
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Answer:
The hippocampus volumes in the alcoholic adolescents are less than the normal volume of 9.02 cm³
Step-by-step explanation:
Let x= the hippocampus volumes in the alcoholic adolescents
We'll conduct a hypothesis test at the 0.01 significance level with
Null hypothesis: x = 9.02 cm³
Alternate hypothesis: x < 9.02 cm³
A sample of 13 alcoholic adolescents gives the parameters
size=N= 13
mean=M= 8.12 cm³
standard deviation= s= 0.8 cm³
According to the sample, with 99% confidence, t statistic for the value X=9.02 can be found using the formula:
t= where
- M is the sample mean (8.12)
- s is the standard deviation of the sample (0.8)
- N is the sample size (13)
If we put these numbers in the formula:
t= =4.056
One tailed critical value for the sample with 12 degrees of freedom (sample size-1) in 99% confidence level is 2.681.
Since t value (4.056) is bigger than the critical value, we fail to reject the alternate hypothesis, therefore reject the null hypothesis and accept alternate hypothesis.
The parameterize is 128
In mathematics, and extra in particular in geometry, parametrization (or parameterization; additionally parameterization, parametrization) is the method of locating parametric equations of a curve, a surface, or, greater typically, a manifold or an expansion, described by using an implicit equation.
"To parameterize" by means of itself method "to specific in terms of parameters". Parametrization is a mathematical technique that includes expressing the state of a system, system, or model as a feature of some independent portions referred to as parameters.
Instance 1. find a parametrization of the road through the points (three,1,2) and (1,0,5). answer: the road is parallel to the vector v=(3,1,2)−(1,0,five)=(2,1,−3). subsequently, a parametrization for the line is x=(1,0,five)+t(2,1,−3)for−∞
volume by both the methods
Directly step
{(n-y) dx+(x+y) by = √(3 co
{{(x-y)dx+(x+y) by =
ts-8 sin(t)) (8 sinct) df
t=o + (8 cost+ 8 sinds) 8 cast, dt]
25
(64 cosit,sin (4) +64 sin'? (+ 64 cs) +64 cost) sint) at
205
-(ou (ents) cost() dt = } 64 dt =64() ?
+
=
64 (211-0)
=1281
using Green's Thoerem. Step (2)
- §pdxxQdy = SS (2(244) - 2. (214) G
Jy
D
dA
=
SSC- (U)dA= [[2dA = 2 [SdA
D
D
=24
=2 182
where (A=112 area of the
= 128
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