Answer:
In the presence of salt water and oxygen the coating will not corrode. As long as zinc coating is present and remains intact corrosion is not possible.
Explanation:
Here it is given that a tin is present so firstly tin is made of a chemical element
which belongs to carbon family in periodic table of group 14.
It is a silvery,soft, white metal with a bluish tinge.
Now the covering which is been done on the tin is Zinc.
so, zinc is known to be served as a sacrificial coater.
Their is an amazing reason behind zinc coating being so effective and intact i.e. Its own corrosive properties are such that it stops corrosion.
Their is a process which is known as a galvanic corrosion which refers to that "ZINC" defers to the metal to which it is protecting.
It is even more electrochemically active than iron itself.
Here, it is mentioned that zinc coating gets chipped but the coating remains intact. So, if the zinc is not removed from the tin's surface it will not get corroded when it is exposed to salt water and oxygen.
Answer:
28.52 L
Explanation:
First, let's calculate the density of the ocean, which is the mass divided by the volume:
d = m/V
d = 35.06/1
d = 35.06 g/L
So, for a mass of 1.00 kg = 1000.00 g
d = m/V
35.06 = 1000.00/V
V = 1000.00/35.06
V = 28.52 L
How all the data are expressed with two significant figures, the volume must also be expressed with two.
The isomers are:
CH3CH2CH2CH2-Br most responsive, recause there is slightest gathering around the essential carbon iota for the nucleophile to assault.
(CH3)2CHCH2-Br second generally responsive.
.......Br
.......|
CH3CHCH2CH3 thid generally responsive.
(CH3)3C-Br slightest receptive. It is, be that as it may, energetically responsive in a Sn1 response. This is on the grounds that (CH3)3C+ is an exceptionally stable carbonium particle.
2<span>H2SO4</span> + <span>Pb(OH)4</span> = <span>Pb(SO4)2</span> + 4<span>H2O</span>