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3 years ago

Which represents the ionization of a strong electrolyte?

2 answers:

5 0

The answer is K3PO4(s) → 3K+(aq) + PO43–(aq) since water-soluble ionic tripotassium phosphate dissociates completely into K+ and PO43– ions when dissolved, that is, no K3PO4 remains in the solution. Carbonic acid H2CO3 and acetic acid CH3COOH are weak electrolytes since they are weak acids that do not completely ionize, while nonelectrolyte CH3OH do not dissociate into ions.

nevsk [136]3 years ago

3 0

Answer:

K3PO4(s) → 3K+(aq) + PO43–(aq)

Explanation:

You might be interested in

Calculate the concentration of OH- in a solution that contains 3.9 x 10-4 M H3O+ at 25°C. Identify the solution as acidic, basic

aalyn [17]

Answer:

[OH⁻] = 2,6x10⁻¹¹

Acidic

Explanation:

The kw in water is:

2 H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)

kw = [OH⁻] [H₃O⁺] = 1,00x10⁻¹⁴

If concentracion of H₃O⁺ is 3,9x10⁻⁴M:

[OH⁻] [3,9x10⁻⁴M] = 1,00x10⁻¹⁴

[OH⁻] = 2,6x10⁻¹¹

pH is defined as - log[H₃O⁺]. If pH>7,0 the solution is basic, if pH<7,0 solution is acidic, if pH=7,0 solution is neutral.

In this problem,

pH = - log [3,9x10⁻⁴M] = 3,4

As pH is < 7.0, the solution is acidic

I hope it helps!

8 0

3 years ago

How much heat will be given off when 1500 g of water cools down by 20 C? please help and explain:)))

docker41 [41]

Answer:

126000J

Explanation:

From the question given, we obtained the following information:

M = 1500g

C = 4.2J/g°C

ΔT = 20°C

Q =?

Q= MCΔT

Q = 1500 x 4.2 x 20 =

Q = 126000J

7 0

3 years ago

A 44.8 g rhodium sample contains how many rhodium atoms

Tresset [83]

Answer:

2.63*10^23

Explanation:

1 mol rhodium = 102.91

44.8g/1 mol * 1 mol/ 102.91mol * 6.022*10^23/1 mol =

2.63*10^23

6 0

3 years ago

(01.07 LC)

Rasek [7]

The most accurate measurement is 1.1 g. Option A

<h3>What is accuracy?</h3>

The term accuracy refers to the fact that the measurement is close to the true value. The closer the measurement is to the true value as given, the more accurate it is.

In this case, the true value of the mass of the sample of calcium carbonate is 1.134 g. Now we have to look at all the masses of as obtained by Emma during the experiment.

The most accurate measurement is 1.1 g. Option A

Learn more about accuracy:brainly.com/question/15276983

#SPJ1

8 0

2 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

Answer: The amount of oxygen gas consumed by mouse is 0.202 grams.

Explanation:

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

3 years ago