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2 years ago

Which of the following situations best shows deposition?

Chemistry

1 answer:

KATRIN_1 [288]2 years ago

8 0

Answer:

chemistry, deposition occurs when molecules settle out of a solution. Deposition can be viewed as a reverse process to dissolution or particle re-entrainment. It is a phase change from the gaseous state to a solid, without passing through the liquid state, also called re-sublimation.

Explanation:

Examples include beaches, deltas, glacial moraines, sand dunes and salt domes. In severely cold temperatures frost will form on windows because the water vapor in the air comes into contact with a window and immediately forms ice without ever forming liquid water.

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Which of the following will be most soluble in octane?

natima [27]

Answer:

CH3CH3CH2CH3

Explanation:

Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.

It belongs to a special group of hydrocarbons called alkanes.

What makes a substance soluble in another?

It is a common phrase that "like dissolves like". This is applicable to solubility of substances in another.

A polar solvent will freely and easily dissolve a polar solute. For example, water and salt.
A non-polar solvent will also dissolve a non-polar solute. This case, hydrocarbons will dissolve themselves.
The first option is a butane, a 4-carbon length hydrocarbon which will be dissolved in octane.
Both compounds are non-polar.

7 0

3 years ago

What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm

disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O) is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to $\frac{5.71}{286}$ = 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is $\frac{0.0199 X 1000}{250}$ = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³

3 0

2 years ago

Difference between Rapid and spontaneous composition

Over [174]

Answer:

spontaneous composition is the ingnition

of the substance due to the repid oxidation of its on material.

There is no requirement of heat of external sources.

Rapid composition on the other hand release large amount of heat and light energy.

Explosion and the firecracker is the best example of Rapid composition.

3 0

3 years ago

Plz help ASAP it’s dude soon

Alex_Xolod [135]

Answer:

Explanation:

6 0

2 years ago

Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added ha

laiz [17]

Answer: the reliability will be worse

Explanation:

Suppose we used 0.5 M NaOH to titrate our vinegar sample instead of 0.1 M.

Now by using 0.5M instead of 0.1M we are increasing the concentration of NaOH,

We know that the moles used = Volume x concnetration.

so for the same no of moles, if the concentration increases, the volume decreases.

Hence it will consume less NaOH.

now Since the volume decreases, the titration volume of less number will increase the % error.

Therefore the reliability will be worse.

4 0

2 years ago