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uysha [10]
3 years ago
15

How do non contact forces affect the world around us

Chemistry
1 answer:
dolphi86 [110]3 years ago
3 0
A Non Contact Force is a force which acts on an object without coming physically in contact with it.[1] The most familiar example of a non-contact force is gravity, which confers weight.[1] In contrast a contact force is a force applied to a body by another body that is in contact with it.[1]
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If u answer will answer the brainlest
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Answer:

the electricity dissipated, because of the time.

Explanation:

electricity dissipates.

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2 years ago
The negatively charged particles of an atom are the
posledela

Answer:

Electron: A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.

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A certain liquid X has a normal boiling point of 108.30 °C and a boiling point elevation constant Kb=1.07 °C kg/mol. A solution
Fynjy0 [20]

Answer:

34,6g of (NH₄)₂SO₄

Explanation:

The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:

ΔT = kb×m

Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.

For the problem:

ΔT = 109,7°C-108,3°C = 1,4°C

kb = 1.07 °C kg/mol

Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:

0,785 moles of ions×\frac{1(NH_{4})_{2}SO_{4}}{3Ions} = 0,262 moles of (NH₄)₂SO₄

As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

0,262 moles of (NH₄)₂SO₄×\frac{132,14g}{1mol} = <em>34,6g of (NH₄)₂SO₄</em>

<em></em>

I hope it helps!

7 0
3 years ago
If a Ferrari with an initial velocity of 10m/s accelerates at a rate of 5m/s2 for 3 seconds. What will it’s final velocity be?
Reika [66]

Answer:

<em><u>V = 25 m/s</u></em>

Explanation:

From first equation of motion, V = U + at

V = 10 + ( 5×3 )

V = 25 m/s

4 0
3 years ago
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