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3 years ago

How do non contact forces affect the world around us

1 answer:

3 0

A Non Contact Force is a force which acts on an object without coming physically in contact with it.[1] The most familiar example of a non-contact force is gravity, which confers weight.[1] In contrast a contact force is a force applied to a body by another body that is in contact with it.[1]

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In a chemical reaction, a certain compound changes intoanother compound at a rate proportional to the unchanged amount. ifinitia

Nadya [2.5K]

No it will be a 10% of that balance so take 16 * 10% and then take that answer and divide bye 70%

7 0

3 years ago

Sedimentary rocks are changed to metaphoric rocks through seduction and _____________?

Nana76 [90]

Hello,

Here is your answer:

The proper answer to this question is "deposition".

Your answer deposition.

If you need anymore help feel free to ask me!

Hope this helps!

7 0

3 years ago

which piece of equipment would be used to measure the volume of a liquid? a. a beaker b. a meter stick c. a graduated cylinder d

Ulleksa [173]

It is a graduated cylinder.

3 0

2 years ago

If 3 g of element C combine with 8 g of element D to form compound CD, how many grams of D are needed to form compound CD2?

bija089 [108]

<span>For the answer to the question above,
If 3g of element combines with 8g of D to form CD it means
1 mole of C = 3g
1 mole of D = 8g
hence it forms CD.
So to form CD2 you need 16g of element D
I hope my answer helped you</span>

8 0

3 years ago

As a technician in a large pharmaceutical research firm, you need to produce 250. mL of a potassium dihydrogen phosphate buffer

Reika [66]

Answer:

We will need 147.772 mL of KH2PO4 to make this solution

Explanation:

For this case we can give the following equation:

H2PO4 - ⇄ H+ + HPO42-

With following pH- equation:

pH = pKa + log [HPO42-]/[H2PO4-]

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

-0.16 = log [HPO42-]/[H2PO4-]

10^-0.16 = [HPO42-]/[H2PO4-]

0.6918 = [HPO42-]/[H2PO4-]

Let's say the volume of HPO42-= x then the volume of H2PO4- will be 250 mL - x

Since both have a concentration of 1M = 1 mol /L

If we plug this in the equation 0.6918 = [HPO42-]/[H2PO4-]

0.6918 = x / (250 - x)

0.6918*250 - 0.6918x = x

172.95 = 1.6918x

x = 102.228 mL

The volume of HPO42- = 102.228 mL

Then the volume of H2PO4- = 250 - 102.228 = 147.772 mL

To control this we can plug this in the pH equation

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

7.05= 7.21 + log (102.228 / 147.772) = 7.05

We will need 147.772 mL of KH2PO4 to make this solution

3 0

3 years ago