Question

Simplify 2x^2-7x-4/x^2-5x+4 What are the excluded values

Answer 1

Answer:

x = 1

Step-by-step explanation:

Given

$\frac{2x^2-7x-4}{x^2-5x+4}$ ← factor numerator and denominator

= $\frac{(x-4)(2x+1)}{(x-4)(x-1)}$ ← cancel (x - 4) on numerator/ denominator

= $\frac{2x+1}{x-1}$

The denominator of the rational expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x - 1 = 0 ⇒ x = 1 ← excluded value

Answer 2

Answer:

On edge it is D, 1 and 4

Step-by-step explanation:

Why was it impossible to find this answer