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Answer:
R(p) = -3500p^2 +48000p . . . revenue function
$6.86 . . . price for maximum revenue
Step-by-step explanation:
The 2-point form of the equation for a line can be used to find the attendance function.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (27000 -20000)/(6 -8)(x -8) +20000
y = -3500(x -8) +20000
y = 48000 -3500x . . . . y seats sold at price x
The per-game revenue is the product of price and quantity sold. In functional form, this is ...
R(p) = p(48000-3500p)
R(p) = -3500p^2 +48000p . . . per game revenue
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Revenue is maximized when its derivative is zero.
R'(p) = -7000p +48000
p = 48/7 ≈ 6.86
A ticket price of $6.86 would maximize revenue.
Multiply the length by 2, then multiply the width by 2 and then add them together.
7 3/4 x 2 = 15 1/2
4 1/3 x 2 = 8 2/3
15 1/2 = 31/2
8 2/3 = 26/3
Find common denominator:
31/2 x 3 = 93/6
26/3 x 2 = 52/6
93/6 + 52/6 = 145/6
145/6 = 24 1/6 inches.
Answer:
0.049
4.9 % of probability
Step-by-step explanation:
The probability of having the disease is equal to 7%
The probability of testing positive, having the disease is equal to 70%
We are looking for the probability of testing positive.
For that, we need to multiply the probabilities to find the result
P = (0.07)*(0.7)
P = 0.049
P = 4.9%
There are one 4/5 in 1 cus (1=5/5)
75 meters did he walk everyday por just 5 days