The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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Step-by-step explanation:
1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.
2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)
3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)
4. that means that ΔADB ≅ΔCDB via SSS rule.
5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)
Hope this helps! :)
Answer:
The triangle is a right triangle
Step-by-step explanation:
For the triangle to be right, Pythagoras’ theorem must be obeyed
According to the theorem, the square of the longest side (the hypotenuse) equals the sum of the squares of the two other sides
Now, from the given side lengths, the highest value is 10;
squaring this, we have 10^2 = 100
Squaring and adding the other values, we have
6^2 + 8^2 = 36 + 64 = 100
This mean the values are equal and the Pythagoras’ theorem is obeyed
Hence, we can conclude that the triangle with the given side lengths is a right triangle
No, because the 3 is repeating. If the x axis(domain) ever repeats, it’s not a function.
X-axis is domain
Y-axis is range
