Ba(OH)₂ + 2HCl = BaCl₂ + 2H₂O
n(HCl)=c(HCl)v(HCl)
n{Ba(OH)₂)}=c{Ba(OH)₂}v{Ba(OH)₂}=2n(HCl)=2c(HCl)v(HCl)
v{Ba(OH)₂}=2c(HCl)v(HCl)/c{Ba(OH)₂}
v{Ba(OH)₂}=2*0.250*0.020/0.100=0.100 L = 100 mL
The answer will be apart of a 60 caculace so it will equal to a efficacy amount so d
Explanation:
Since, the given reaction is
Sum of masses on both reactant and product side is as follows.
235.043924 + 1.008665 = 139.921620 + 93.915367 + (2 × 1.008665)
= 0.198272 u
As it is known that relation between energy and mass is as follows.
Energy produced =
Since, 1 u = 931.494 MeV/. Putting this value into the above formula as follows.
Energy produced =
=
= 184.69 MeV
As 1 MeV equals joules.
Hence, 184.69 MeV will be converted into joules as follows.
= J
= J
Thus, we can conclude that energy released in this reaction is J.
The number of unique open-chain structures corresponding to the molecular formula C₃H₅Cl is two.
<em>Step 1</em>. Draw <em>all possible connections of three carbon atoms</em>.
The is only one possibility (See first image below).
<em>Step 2</em>. Put the <em>Cl in all possible unique positions</em>.
There are only <em>two</em> possibilities: on an end carbon or on the middle carbon (see second image below).
Thus, there are only two isomers of C₃H₅Cl.