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2 years ago

What is reduction potential?

Chemistry

2 answers:

Shtirlitz [24]2 years ago

8 0

Answer:

A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.

Explanation:

Nuetrik [128]2 years ago

4 0

A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons

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If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol

Lelu [443]

<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

$P_{1}V_{1}=P_{2}V_{2}$

Where,

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

$V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L$

Remember, 1 L is equal to 1000 mL.

So,

$125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L$

So, calculating the new volume, we have:

$P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm$

Hence, the new pressure is 1.67 atm.

Have a nice day!

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3 years ago

Please help, 15 points

oee [108]

1rst is D, second is A

Explanation:

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3 years ago

What is the pH of a 0.050 M triethylamine, (C2H5)3N, solution? Kb for triethylamine is 5.3 ´ 10-4. Question options: 1) 11.69 2)

blsea [12.9K]

<span>the pH of a 0.050 M triethylamine, is 11.70
</span>
For triehtylamine, $(C_{2}H_{5})_{3}N$ , the reaction will be
$(C_{2}H_{5})_{3}N + H_{2}O ---\ \textgreater \ ( C_{2}H_{5})_{3}NH^{+} + OH^{-}$

and we know, pH = -log[H+] and pOH = -log[OH-]

Also, pOH + pH = 14

Now, the Kb value = 5.3 x 10^-4

And $kb = \frac{( [( C_{2}H_{5})_{3}NH^{+} ]* OH^{-} )}{[( C_{2}H_{5})_{3}N]}$

thus, [OH-] =(5.3 ^ 10-4) ^2 / 0.050

=0.00516 M

Thus, pOH = 2.30
pH = 14 - pOH = 11.7

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8.0g's of water is your answer

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3 years ago

What is reduction potential?​

What is reduction potential?