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weeeeeb [17]
3 years ago
5

Mr.Johnson leaves on a trip planning to travel 24 mph

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0
In conclusion, she is very slow
Artist 52 [7]3 years ago
4 0
Ummm is this a full question?
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The system of equations above is graphed below. Find the solution to the system.
Oksana_A [137]

Option D: x=3,y=-2 is the solution to the system of equations.

Explanation:

Given that the equations are 4x+y=10 and 2x+y=4

We need to determine the solution of the system of equations.

The solution can be determined by solving the two equations.

Let us solve the system of equations using substitution method.

Consider the equation 4x+y=10 , the value of y is given by

y=10-4x

Substituting the value of y=10-4x in the equation 2x+y=4 , we get,

2x+(10-4x)=4

Simplifying, we get,

2x+10-4x=4

     -2x+10=4

             -2x=-6

                 x=3

Substituting the value of x=3 in 4x+y=10 , we get,

4(3)+y=10

  12+y=10

         y=-2

Thus, the solution to the system of equations is x=3,y=-2

Hence, Option D is the correct answer.

7 0
3 years ago
Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends a
djverab [1.8K]

50 = 3x + 2

50 - 2 = 3x

48 = 3x

48/3 = 3x/3

16 = x


Jack has 16 friends.

4 0
3 years ago
Read 2 more answers
Exercise 5.2. Suppose that X has moment generating function
soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Step-by-step explanation:

Given:

moment generating function  of X as:

MX(t) = \frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}

a)  Now

Mean, E(X) = M_{X}'(t=0)

Thus,

M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}

or

M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}

also,

E(X^{2})=M_{X}''(t=0)

Thus,

M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}

or

M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}

Therefore,

Mean, E(X) = M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}

or

Mean, E(X) = - 0.5

and

E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}

or

E(X^{2}) = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Therefore,

at x = 0, P(x) = \frac{1}{2}

at x= - 4 ,P(x) = \frac{1}{3}

at x = 5, P(x) = \frac{1}{6}

Thus,

E(X) =\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})

or

E(X) = - 0.5

also,E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})

E(X^{2})  = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0
4 years ago
Which of the following methods of sampling is an example of a stratified random sample?
Juliette [100K]

Answer: D

Step-by-step explanation:

7 0
3 years ago
Which expression has a value of 3
marta [7]
I think the answer is a or d not sure
8 0
4 years ago
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