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3 years ago

Mr.Johnson leaves on a trip planning to travel 24 mph

Mathematics

2 answers:

dmitriy555 [2]3 years ago

5 0

In conclusion, she is very slow

Artist 52 [7]3 years ago

4 0

Ummm is this a full question?

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Tyler bought 20 shares of Wal-Mart at $48.80. A year later, he bought 20 more shares at $54.60. He later sold all of his shares

NARA [144]

He bought last year and year later total is $104.3

Each share he sold 62.80 with tax is 0.03

62.80x1.03= $64.684 for each share
So there are 40 shares

64.684 x 40= $2587.36

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2 years ago

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Given the following measurements, calculate the minimum and maximum possible object. Round to the nearest square whole square un

garri49 [273]

Answer:

28.3 centimeters and 21 centimeters

Step-by-step explanation:

28.3 + 0.05) cm, so 28.25 cm ≤ length < 28.35 cm.

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3 years ago

CAN SOMEONE PLEASE HELP ME, with the worksheet will MARK AND 5 STARS!!!

mote1985 [20]

Answer:

26 miles per houre

Step-by-step explanation:

sow you put 450 amd 3.4 so you subtract but first you gat to put on the 45.0 -3.4 and then you git youre answred

4 0

3 years ago

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The scores of individual students on the American College Testing (ACT) Program College Entrance Exam have a normal distribution

tekilochka [14]

Answer:

The probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

Step-by-step explanation:

Xi~N(18.6, 6.0), n=400, Yi~Ber(p); Z~N(0, 1);

$P(0\leq X\leq 19.0)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{19-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}, \mu=18.6, \sigma=6.0$

$P(-3.1\leq Z\leq 0.0667)=\Phi(0.0667)-\Phi (-3.1)=\Phi(0.0667)-(1-\Phi (3.1))=0.52790+0.99903-1=0.52693$

P(Xi≥19.0)=0.473

$\{Yi=0, Xi< 19\\Yi=1, Xi\geq 19\}$

p=0.473

Yi~Ber(0.473)

$P(\frac{1}{n}\displaystyle\sum_{i=1}^{n}X_i\geq 19)=P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)$

Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{n}X_i\~{}N(n\mu, \sqrt{n}\sigma),\displaystyle\sum_{i=1}^{400}X_i\~{}N(7440, 372)$

Then:

$P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)=1-P(0$

$P(\displaystyle\sum_{i=1}^{n}Y_i=1)=P(\displaystyle\sum_{i=1}^{400}Y_i=1)$

Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{400}Y_i\~{}N(400\times 0.473, \sqrt{400}\times 0.499)=\displaystyle\sum_{i=1}^{400}Y_i\~{}N(189.2; 9.98)$

$P(\displaystyle\sum_{i=1}^{400}Y_i=1)\~{=}P(0.5$

Then:

the probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

7 0

3 years ago

Nigel borrows $250 and pays 5.5% simple interest each year. if he pays back the money in one year, what is the total amount that

ddd [48]

Answer: $263.75

Step-by-step explanation:

5.5= 0.055

250x.055=263.75

7 0

2 years ago

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