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podryga [215]
3 years ago
14

Help plz ASAP !!!!!!!!!

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

The answer is D: 18%

Step-by-step explanation:

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John is 31 and Jenny is  26

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Find the value of y in the equation 3/y-2=8
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Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly​ low, μ- 2σ ​, and the maximum val
allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\

Using the binomial distribution: \mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186

In this the maximum value which is significantly​ low, \mu-2\sigma, and the minimum value which is significantly​ high, \mu+2\sigma, that is equal to:

\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56

3 0
3 years ago
Help, how would I get my answer for this question?
Maslowich

Answer:

(-4,32)

Step-by-step explanation:

Given points are (-1,-8)

And given transformation is D_4 r_{x-axis}

We will start from left to right.

First transformation is reflection about x-axis.

When we reflect about x-axis (x,y)\ became\ (x,-y)

So, (-1,-8)=[-1,-(-8)]=(-1,8)

Now next transformation is dilation with a factor 4.

If we do dilation with a factor 'k' to the point (x,y)

New co-ordinates after dilation became (kx,ky)

So, (-1,8)\ became\ (-4,32)

8 0
3 years ago
F(x) = |6x| - 2 ; reflection in y-axis
dedylja [7]

Hope this helps you. Thank you....

6 0
3 years ago
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