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3 years ago

I NEED HELP ON THIS PROBLEM QUICKLY PLEASE THANK YOU

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Note that:

i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i

and after that the pattern repeats. Using the rules of exponents, i^12*(i^13)^3 = i^51 = (i^4)^12 * i^3 = 1*(-i) = -i.

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–12 – 4.8 ∙ (–2 + –8) whats this equal need hlp asap 10 pts and i will befreind

trasher [3.6K]

-16.8 * -10= 168 is the answer

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3 years ago

What is x plus y equals 20

Rufina [12.5K]

You would have to find the y intercepts.

X + Y = 20

Substitute 0 for y then your answer would be 20 for x.

Substitute 0 for x then your answer would be 20 for y.

X=20

Y=20

Hope it helped! : )

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4 years ago

Read 2 more answers

Solve the following equation algebraically show the steps: <br><br><br> n/3 -5 = 5

Lana71 [14]

$\longrightarrow{\green{ \: n = 30 }}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$\frac{n}{3} - 5 = 5$

➼ $\: \frac{n}{3} = 5 + 5$

➼ $\: \frac{n}{3} = 10$

➼ $\: n = 10 \times 3$

➼ $\: n = 30$

Therefore, the value of n is 30.

$\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}$

$\frac{30}{3} - 5 = 5$

✒ $\: 10 - 5 = 5$

✒ $\: 5 = 5$

✒ $\: L.H.S.=R. H. S$

Hence verified.

$\bold{ \green{ \star{ \orange{Mystique35}}}}⋆$

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3 years ago

What is 9 ^ 5? Need this fast!!!

Zielflug [23.3K]

9^5 is 45
As, 9+9+9+9+9 =45

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3 years ago

Hi, can you help to find (all the roots/zeros), please!!!

OLga [1]

Solution

Given the quadratic equation

$x^2-2x-38=0$

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

$\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\ \\ \Rightarrow x^2-2x=38 \end{gathered}$

Step 2: add the square of half of the coefficient of x to both sides

That is;

$\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\ \\ \Rightarrow x^2-2x+1=38+1 \\ \\ \Rightarrow x^2-2x+1=39 \\ \\ \Rightarrow(x-1)^2=39 \end{gathered}$

Step 3: Simplify the above expression;

$\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\ \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}$

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1 year ago