1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
In-s [12.5K]
2 years ago
9

Find area of triangle .. help me please!

Mathematics
2 answers:
Zinaida [17]2 years ago
3 0

Answer:

12 x 6 = 72, 72 divided by 2 ( x 1/2) = 36 yd^2

Formula of a triangle:

BH x 1/2

In this case 12 is your base and 6 is your height.

Anastaziya [24]2 years ago
3 0

Answer:

A = 36 yd²

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = 12 and h = 6 , then

A = \frac{1}{2} × 12 × 6 = 6 × 6 = 36 yd²

You might be interested in
The The geometrics decide to play a concert in the gym. The gym measures 100 feet long by 60 feet wide by 30 feet tall. The band
hammer [34]
So what you do is multiply 60, 30, and 100 together to get 180,000. Then divide 180,000 by 18,000 (simplify it to 180 ÷ 18) and the answer is 10. So they could turn it up 10 notches.
7 0
3 years ago
At the park, there is a triangular sandbox with base = 12ft and height = 4ft. A drawing of the sandbox is shown above. Brie want
sammy [17]

Your question is not clear, but it looks as though you want to know how Brie can make a similar sandbox with base = 8ft.

Answer:

For Brie to make a similar sandbox, he must use a base = 8ft, and height = (8/3)ft

Step-by-step explanation:

It is possible for Brie to make a similar triangular sandbox with base = 12ft and height = 4ft.

All he must ensure is that the ratio of base to height of the original sandbox is the same ratio of base to height of the one he is trying to make.

The original sandbox is 12:4

Because he wants to use a base = 8ft, the sandbox he is trying to make is 8:x

Where x is the height of the sandbox he is trying to make.

Then for these sandboxes to be similar, the ratio 12:4 = 8:x

=> 12/4 = 8/x

12x = 8 × 4

12x = 32

x = 8/3

The height must be (8/3)ft

3 0
3 years ago
A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of
krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

QR=chord =radius =R

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus QO=\frac{R}{2}=RO

In triangle PQO applying Pythagoras theorem

(PQ)^2=(PO)^2+(QO)^2

PO=\sqrt{(PQ)^2-(QO)^2}

PO=\sqrt{R^2-\frac{R^2}{4}}

PO=\frac{\sqrt{3}}{2}R

Thus length of Side of square =2PO=\sqrt{3}R

Area of square=(\sqrt{3}R)^2=3R^2

Area of Circle=\pi R^2

Ratio of square to the circle=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }

5 0
3 years ago
How can I make this true 24 times 3 plus 4=90 true
eimsori [14]
24 times 3= 72+4=76+14=90
                                      ^
5 0
3 years ago
Read 2 more answers
Mr. Daniels is organizing a class trip on a budget of $900. The bus rental costs $600. Mr. Daniels will also buy tickets that co
Mars2501 [29]

Answer:

Mr.Daniels is a fajjett

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the endpoint formula given midpoint?
    6·1 answer
  • Solve for t. 100-3t=76
    9·3 answers
  • I need help with this question I wasn’t sure on what to pick as the answer.
    6·1 answer
  • A-B=56 A:B is equivalent to 9:2
    12·1 answer
  • W^2+13w+36=(w+4)(w+?)
    6·2 answers
  • What is the percentage plz help me with this Question.
    11·2 answers
  • Calculate the rate of change for the following data
    6·1 answer
  • Graph the equation y=-3x-4 by plotting points
    12·1 answer
  • ⚠️⚠️PLASE HELP ME SOLVE AS SOON AS POSSIBLE⚠️⚠️​
    8·1 answer
  • The temperature in a town is 37.5°F during the day and -7.6°F at night. Find the difference in the temperatures
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!