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2 years ago

Find the perimeter of each polygon. Assume that lines which appear to be tangent are tangent.

Mathematics

1 answer:

ratelena [41]2 years ago

4 0

9514 1404 393

Answer:

34.8

Step-by-step explanation:

The only polygon in the figure is the triangle outlined in red. Its perimeter is the sum of its side lengths: 15 +6.1 +13.7 = 34.8 units.

The two halves of the chord are the same length.

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A point is randomly chosen on a map of North America. Describe the probability of the point being in each location: North Americ

Aleks04 [339]

Answer:

We know that the map is of North America:

The probabilities are:

1) North America:

As the map is a map of North America, you can point at any part of the map and you will be pointing at North America, so the probability is p = 1

or 100% in percentage form.

2) New York City.

Here we can think this as:

The map of North America is an extension of area, and New Yorck City has a given area.

As larger is the area of the city, more probable to being randomly choosen, so to find the exact probability we need to find the quotient between the area of New York City and the total area of North America:

New York City = 730km^2

North America = 24,709,000 km^2

So the probability of randomly pointing at New York City is:

P = ( 730km^2)/(24,709,000 km^2) = 3x10^-5 or 0.003%

3) Europe:

As this is a map of Noth America, you can not randomly point at Europe in it (Europe is other continent).

So the probaility is 0 or 0%.

5 0

3 years ago

Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic

kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by, α = 36 / day

Truck operation departure rate is given, β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

$w_{s} = \frac{1}{\alpha - \beta }$

where $w_s$ is waiting time in system

$\alpha$ is arrival rate described Poission distribution

$\beta$ is service rate described by Exponential distribution

$w_{s} = \frac{1}{\alpha - \beta }$

$w_{s} = \frac{1}{48 - 36 }$

$w_{s} = \frac{1}{12 } day$

$w_{s} = \frac{1}{12 } \times 24 hour$ ...it is due to 1 day = 24 hours

$w_{s} = 2 hours$

Therefore, time required for waiting in system is 2 hours.

5 0

3 years ago

Samantha is making a quilt and she has determined she needs 450 square inches of yellow fabric and 478

asambeis [7]

Conversions:

1 yard = 36 inches

The store only sells fabric by the by the quarter yard.

<h2><u><em>The yellow fabric: 450/36 = 12.5 square yards</em></u></h2><h2><u><em>The blue fabric: 478/36 is around 13.3 square yards</em></u></h2>

Total Amount: 12.5+13.3=

<h2><u><em>25.8 square yards</em></u></h2>

7 0

2 years ago

Plz help me with this

shtirl [24]

2x-7y=18 _(1)
-2x+4y=5

11y=23 , Y=23/11 sub in 1

2x-7×23/11=18

2x = 18×11 + 7×23

x = ( 198 + 161 )/2 = 359/2

5 0

3 years ago

No files please!!!!!!!!!!!!!!

Lisa [10]

Answer:

1.y=x-4

2.y=−2x+5

Step-by-step explanation:

6 0

3 years ago