for 6
in a
given
slope(m)=1
point=(2,-4)=(x1,y1)
we know
equation of straight line
y-y1=m(x-x1)
y+4=1(x-2)
y+4=x-2
therefore x-y-6=0 is the required equation
substituting with ax+by+c=0 we get
a=1
b= -1
c= -6
Important notes:
3 sides 1 angle - COSINE RULE
2 sides 2 angle - SINE RULE
since, the question wants to find the length of BC. In the end we will have 3 sides and 1 angle and use cosine rule
formula of cosine rule:
a² = b² + c² - 2bc Cos A° (to find the length)
Cos A° = b² + c² - a² / 2bc ( to find the angle, if there is given three sides and have to find the angle)
So just substitute,
a² = 13² + 15² - 2(13)(15) Cos 95°
a = 20.6 or 21
Answer:
Opens downward, like a frowning face
Step-by-step explanation:
So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
Divide 100 to 56 = 56/100= 0.56 then you wanna times it by 50 so then it would be.56x50=28
