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telo118 [61]
2 years ago
11

5.

Mathematics
1 answer:
adell [148]2 years ago
5 0

Answer:

Solving the inequality 3x -2 < 4 we get \mathbf{x

Option D is correct option.

Step-by-step explanation:

We need to solve the inequality 3x -2 < 4 and find value of x

Solving the inequality for finding value of x, we will keep x on left side of inequality and all other terms on the right side.

3x -2 < 4

Adding 2 on both sides

3x -2+2 < 4+2\\3x < 6

Now, we will divide 3 on both sides

\frac{3x}{3}

So, we get x < 2

Solving the inequality 3x -2 < 4 we get \mathbf{x

Option D is correct option.

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What is the slope pls help
Galina-37 [17]

Answer:

y=.5x+-2.5

Step-by-step explanation:

This is the linear equation (y=mx+b) m means slope so your slope is .5.

7 0
3 years ago
!!SOMEBODY PLEASE HELP ME OUT!!<br><br>What is the slope of the line??​
AlladinOne [14]

Answer:

i think it's -1 / -1

nut i'm not sure so if its wrong then sorry , and don't thank's me...

5 0
2 years ago
if i have 19 friends they each want 3 slices of cake i have 38 slices how do i divide and get a simple remainder.
Salsk061 [2.6K]
38 divided by 19 than multiply by 3
3 0
3 years ago
A drilling crew dug to a depth of 26 ½ feet during their first day of drilling. On the second day, the crew dug down 9½ feet mor
Neporo4naja [7]

The depth of the bottom of the hole after the second day is 36 feet using addition operation.

<h3>What is addition?</h3>

In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the sum refers to the outcome of the operation.

Given the depth on the first day is 26 ½ feet.

Depth on the second day = 9½ feet more than on the first day i.e. 9½ feet + depth on the first day

This implies, depth on the second day = 9½ + 26 ½

= 36 feet

Therefore, the depth of the bottom of the hole after the second day is 36 feet.

To learn more about addition, visit:

brainly.com/question/25621604

#SPJ9

5 0
1 year ago
Can't figure it out!!
Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby &#10;\begin{array}{llll}&#10;average\ rate\\&#10;of\ change&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;f(x)= \cfrac{1}{x}  \qquad &#10;\begin{cases}&#10;x_1=2\\&#10;x_2=b&#10;\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}&#10;\\\\\\&#10;\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies &#10;\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}&#10;\\\\\\&#10;

\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying&#10;\\\\\\&#10;2b^2-4b-10b+20=0\implies 2b^2-14b+20=0&#10;\\\\\\&#10;b^2-7b+10=0\implies &#10;(b-2)(b-5)=0\implies b=&#10;\begin{cases}&#10;\boxed{5}\\&#10;2&#10;\end{cases}
8 0
3 years ago
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