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I found an image that corresponds to the above question.
The shape was a rectangle. Its width is 7 units, its length is x.
The shaded area of the rectangle forms a trapezoid.
Area of a trapezoid = [(a+b)/2] * h
63 sq. units = (7+x)/2 * 7
63/7 = (7+x)/2
9 = (7+x)/2
9*2 = 7 + x
18 = 7 + x
18 - 7 = x
11 = x
The value of x is 11 units. It is the length of the rectangle.
Area of the trapezoid = (a+b)/2 * h
63 = (7+11)/2 * 7
63 = 18/2 * 7
63 = 9 * 7
63 = 63
The shape was a rectangle. Its width is 7 units, its length is x.
The shaded area of the rectangle forms a trapezoid.
Area of a trapezoid = [(a+b)/2] * h
63 sq. units = (7+x)/2 * 7
63/7 = (7+x)/2
9 = (7+x)/2
9*2 = 7 + x
18 = 7 + x
18 - 7 = x
11 = x
The value of x is 11 units. It is the length of the rectangle.
Area of the trapezoid = (a+b)/2 * h
63 = (7+11)/2 * 7
63 = 18/2 * 7
63 = 9 * 7
63 = 63
We will start with plotting the x coordinates and y coordinates on the graph
The points 1, 2; 2, 2; 3, 2; 4, 2 have been plotted on the graph which has been attached as an image to the solution.
We can see that the value of y is staying constant (2) for all values of x.
Hence, the points represent the equation y = 2.
