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Snowcat [4.5K]
3 years ago
9

Solve mixture problems. George wishes to increase the percent of acid in 50m / of a 15% acid solution in water to 25% acid, how

much pure acid must you add?
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

x = amount of pure acid to be added = 6.67ml

Step-by-step explanation:

George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?

let

x = amount of pure acid to be added

15% of 50 + x = 25% of 50 + x

(0.15 * 50) + x = 0.25(50 + x)

7.5 + x = 12.5 + 0.25x

Collect like terms

x - 0.25x = 12.5 - 7.5

0.75x = 5

x = 5/0.75

x = 6.6666666666666

Approximately,

x = 6.67

x = amount of pure acid to be added = 6.67ml

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Answer:

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Step-by-step explanation:

<u>Given:</u>

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<u>Compound interest:</u>

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3 0
3 years ago
Suppose that you have $6,000 to invest. Which investment yields the greater return over a 10 year period: 7.44% compounded daily
Nikitich [7]
Hi
Here is you answer mate
But don’t forget to mark me the brainliest


Plug the applicable numbers into the compound interest formula and see which is more.
A = p(1+r/n)nt
A = future amount
p =principal investment
r = interest rate as a decimal
n = number times compounded per year
t = time in years

A = 5000(1+.0743/365)365(10)
= 5000(1.000203562)3650 = $10,510.38

A = 5000(1+.075/4)4(10)
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3 years ago
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