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Elden [556K]
2 years ago
14

Write an expression for y more than 2

Mathematics
1 answer:
monitta2 years ago
3 0

Answer:

2 + y

Step-by-step explanation:

all you must do is add y to 2

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Write an equation for the n th term of the arithmetic seqeuence. Then find a{10}. 100,110,120,130
lord [1]

Answer:

100+10n

Step-by-step explanation: a(10)

100+10(10)

100+100 = 200

7 0
3 years ago
According to a commercial, 4 out of 5 dentist recommend a certain brand of toothpaste. Suppose There are 120 dentist in your are
Genrish500 [490]
4/5 recommend, so about 4/5(120) = 96 doctors recommend the brand.
3 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
2 years ago
IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
jekas [21]

Using the normal distribution, it is found that 1851 people would have an IQ less than 115.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 100, \sigma = 15

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{115 - 100}{15}

Z = 1

Z = 1 has a p-value of 0.8413.

Out of 2200 people:

0.8413 x 2200 = 1851.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

5 0
1 year ago
Shape 1 and shape 2 are plotted on a coordinate plane. Which statement about the shapes is true?
Nataliya [291]

Answer:

C)

Step-by-step explanation:

if the shapes were rotated it would be easier to prove that the shape are congruent. Hope this helps :)

7 0
1 year ago
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