Question

Mr.Richards saved $37 by buying his sneakers at the outlet store. He paid $3 less than half the original price of the sneakers. How much did Mr. Richards pay for the sneakers at the outlet store?

Answer 1

Let, the original price of the sneakers be $x.

Given, Mr. Richard paid $3 less that half of the original price.

Half of the original price = $$\frac{x}{2}$

So Mr. Richard paid = $$(\frac{x}{2}-3)$

By buying the sneakers Mr. Richard saved = $37.

That means the subtraction of the original price and the amount Mr. Richard paid is $37.

So we can write the equation as,

$x-(\frac{x}{2}-3) = 37$

$x-\frac{x}{2}+3 = 37$

To solve it for x, first we have to move 3 to the right side by subtracting it from both sides, we will get,

$x-\frac{x}{2}+3-3 = 37-3$

$x-\frac{x}{2}= 37-3$

$x-\frac{x}{2} = 34$

We will subtract the left side now. To subtract fractions we will make the denominators same. Here 2 is the denominator. To make the denominator of x as 2, we will multiply the numerator and denominator of x by 2. So we can write x as $\frac{2x}{2}$.

$\frac{2x}{2} - \frac{x}{2} = 34$

$\frac{(2x-x)}{2} = 34$

$\frac{x}{2}= 34$

Now we will multiply both sides by 2 to get x.

$(\frac{x}{2})(2) = (34)(2)$

$x = (34)(2)$

$x = 68$

So, the original price = $68.

Mr. Richard paid = $($(\frac{68}{2} -3)$ =$ $(34-3)$= $$31$

So we have got the required answer.

Mr. Richard paid $31 for the sneakers.

Answer 2

Mr Richards paid 80 dollars