(x-5)(x+3)=0
x^2+3x-5x-15=0
(x^2+3x) (-5x-15)
x(x+3) -5(x+3)
x-5=0 x+3=0
x=5 OR -3
<span>y" + 9y = 0
m^2 + 9 = 0
m = ± 3i
yH = C1 cos 3t + C2 sin 3t
yP = C3 t sin 3t + C4 t cos 3t
hope this helps </span>
Answer:
I think it is 2 pounds correct me if I am wrong
Step-by-step explanation: