Question

Given g(x)=Squareroot x-4 and h(x)=2x-8, what is g(h(10))

Answer 1

Answer:

$g(h(10)) = 2\sqrt 2$

Step-by-step explanation:

Given

$g(x) = \sqrt {x - 4$

$h(x) = 2x - 8$

Required

$g(h(10))$

First, calculate $g(h(x))$

We have:

$g(x) = \sqrt {x - 4$

This gives:

$g(h(x)) = \sqrt {h(x) - 4$

Substitute $h(x) = 2x - 8$

$g(h(x)) = \sqrt {2x - 8 - 4$

$g(h(x)) = \sqrt {2x - 12$

Substitute $x = 10$

$g(h(10)) = \sqrt {2*10 - 12$

$g(h(10)) = \sqrt {20 - 12$

$g(h(10)) = \sqrt {8$

Split

$g(h(10)) = \sqrt {4} * \sqrt 2$

This gives

$g(h(10)) = 2\sqrt 2$

Answer 2

Answer:

Step-by-step explanation: