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Anettt [7]
3 years ago
10

Given g(x)=Squareroot x-4 and h(x)=2x-8, what is g(h(10))

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

g(h(10)) = 2\sqrt 2

Step-by-step explanation:

Given

g(x) = \sqrt {x - 4

h(x) = 2x - 8

Required

g(h(10))

First, calculate g(h(x))

We have:

g(x) = \sqrt {x - 4

This gives:

g(h(x)) = \sqrt {h(x) - 4

Substitute h(x) = 2x - 8

g(h(x)) = \sqrt {2x - 8 - 4

g(h(x)) = \sqrt {2x - 12

Substitute x = 10

g(h(10)) = \sqrt {2*10 - 12

g(h(10)) = \sqrt {20 - 12

g(h(10)) = \sqrt {8\\

Split

g(h(10)) = \sqrt {4} * \sqrt 2

This gives

g(h(10)) = 2\sqrt 2

Gemiola [76]3 years ago
5 0

Answer:

Step-by-step explanation:

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