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NISA [10]
3 years ago
8

Rate of change of 15

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:A General Note: Rate of Change

The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

Step-by-step explanation:

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I am a number greater than 40,000 and less than 60,000. My ones digit and tens digit are the same. My ten-thousands digit is 1 l
jarptica [38.1K]
I am a number greater than 40,000 and less than 60,000:

40,000 < n < 60,000

This means that:

n = 10,000n₁ + 1,000n₂ + 100n₃ + 11n₄

And also:

4 ≤ n₁ < 6

0 ≤ n₂ ≤ 9

0 ≤ n₃ ≤ 9

0 ≤ n₄ ≤ 9

My ten thousands digit is 1 less than 3 times the sum of my ones digit and tens digit:

n₁ = 3*2n₄ - 1

n₁ = 6n₄ - 1

This means that:

n = 10,000*(6n₄-1) + 1,000n₂ + 100n₃ + 11n₄

n = 60,000n₄ - 10,000 + 1,000n₂ + 100n₃ + 11n₄

n = 60,011n₄ - 10,000 + 1,000n₂ + 100n₃

<span>My thousands digit is half my hundreds digit, and the sum of those two digits is 9:

n</span>₂ = 1/2 * n₃
<span>
n</span>₂ + n₃ = 9
<span>
Therefore:

n</span>₂ = 9 - n₃
<span>
Therefore:

9 - n</span>₃ = 1/2 * n₃
<span>
9 = 1/2 * n</span>₃ + n₃
<span>
9 = 1.5 * n</span>₃
<span>
Therefore:

n</span>₃ = 6
<span>
If n</span>₃=6, n₂=3.
<span>
This means that:

</span>n = 60,011n₄ - 10,000 + 1,000*3 + 100*6

n = 60,011n₄ - 10,000 + 3,000 + 600

n = 60,011n₄ - 6,400

Therefore:

0<n₄<2, so n₄=1.

If n₄=1:

n = 60,011 - 6,400

n = 53,611

Answer:

53,611
3 0
3 years ago
Subtract:30.008 - 23.17.<br> a. 5.229<br> b. 7.543<br> c. 27.691<br> d. 6.838
Virty [35]
D.
30.008 - 23.17 = 6.838
8 0
3 years ago
What is the value of x in the equation 2x + 1/2x + 2(1+x) = 29?
erica [24]

Answer:

<h2>x = 6</h2>

Step-by-step explanation:

2x  +  \frac{1}{2} x + 2(1 + x) = 29

Multiply through by 2

That's

4x + x + 4(1 + x) = 58

<u>Expand</u>

That's

5x + 4 + 4x = 58

9x = 58 - 4

9x = 54

Divide both sides by 9

That's

\frac{9x}{9}  =  \frac{54}{9}

We have the final answer as

<h3>x = 6</h3>

Hope this helps you

5 0
3 years ago
Can anyone help with my homework it would be greatly appreciated.
choli [55]
63.5 if u want working out let me know
3 0
2 years ago
The length of a city’s bus routes are normally distributed with a mean of 14.5 mi and a standard deviation of 3.2 mi.
jeka57 [31]
Thank you for posting your question here at brainly. Please see below answer:

a) What percentage of city bus routes are less than 15 mi? 
56.20820167 ≈ 56.2%

b)What percentage of city bus routes are greater than 20 mi? 
4.282995170  ≈ 4.3 %

c) What percentage of city bus routes are less than 10 mi?
<span>7.98 ≈ 7.98 %</span>
3 0
3 years ago
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