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Arisa [49]
3 years ago
6

Please help now im taking a test

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0
How do you need help?
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1. How many degrees is x<br> .x<br> 41<br> 82<br> 20.5<br> o<br> 41<br> О<br> 10
Alja [10]

Answer:

Option (1)

Step-by-step explanation:

By the inscribed angle theorem inside a circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

\frac{1}{2}[m(arc AB)] = m(∠ABC)

m(arc AB) = 2[m(∠ABC)]

x = 2(41°)

x = 82°

Option (1) is the correct option.

5 0
3 years ago
Find the nth term of this sequence 2 5 8 11 14 ...
mariarad [96]
Each number is added by 3 so it's 17 20 23 26 29 32 35 38 41 and so on.
8 0
4 years ago
Read 2 more answers
Pls help I don't know how to do this​
AVprozaik [17]

Answer:

Vertex, I believe.

7 0
3 years ago
Evaluate the expression when c=4,d=6 and e=10
natima [27]
Errrmmm.... Where is the expression?
6 0
3 years ago
Find the area of the shaded region round to the nearest tenth
Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

6 0
2 years ago
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