Answer:
C' will be located at (-4,-2)
Step-by-step explanation:
Answer: To know whether a radical expression is in simplest form or not you should put the numbers and letters inside the radical in terms of prime factors. Then, the radical expression is in the simplest form if all the numbers and letters inside the radical are prime factors with a power less than the index of the radical
Explanation:
Any prime factor raised to a power greater than the index of the root can be simplified and any factor raised to a power less than the index of the root cannot be simplified
For example simplify the following radical in its simplest form:
![\sqrt[5]{3645 a^8b^7c^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3645%20a%5E8b%5E7c%5E3%7D%20)
1) Factor 3645 in its prime factors: 3645 = 3^6 * 5
2) Since the powr of 3 is 6, and 6 can be divided by the index of the root, 5, you can simplify in this way:
- 6 ÷ 5 = 1 with reminder 1, so 3^1 leaves the radical and 3^1 stays in the radical
3) since the factor 5 has power 1 it can not leave the radical
4) the power of a is 8, then:
8 ÷ 5 = 1 with reminder 3 => a^1 leaves the radical and a^3 stays inside the radical.
5) the power of b is 7, then:
7 ÷ 5 = 1 with reminder 2 => b^1 leaves the radical and b^2 stays inside the radical
6) the power of c is 3. Since 3 is less than 5 (the index of the radical) c^3 stays inside the radical.
7) the expression simplified to its simplest form is
![3ab \sqrt[5]{3.5.a^3b^2c^3}](https://tex.z-dn.net/?f=3ab%20%5Csqrt%5B5%5D%7B3.5.a%5E3b%5E2c%5E3%7D%20)
And you know
it cannot be further simplified because all the numbers and letters inside the radical are prime factors with a power less than the index of the radical.
If you would like to find the value of a in the polynomial, you can do this using the following steps:
(y - 4)(y^2 + 4y + 16) = y^3 + 4y^2 + 16y - 4y^2 - 16y - 64 = y^3 + 4y^2 + ay - 4y^2 - ay - 64
a = 16
The correct result would be 16.
Answer:
52 inches
Step-by-step explanation:
4×13=52 inches
To solve this problem, you must follow the proccedure below:
1. T<span>he block was cube-shaped with side lengths of 9 inches and to calculate its volume (V1), you must apply the following formula:
V1=s</span>³
<span>
s is the side of the cube (s=9)
2. Therefore, you have:
V1=s</span>³
V1=(9 inches)³
V1=729 inches³
<span>
3. The lengths of the sides of the hole is 3 inches. Therefore, you must calculate its volume (V2) by applying the formula for calculate the volume of a rectangular prism:
V2=LxWxH
L is the length (L=3 inches).
W is the width (W=3 inches).
H is the heigth (H=9 inches).
4. Therefore, you have:
V2=(3 inches)(3 inches)(9 inches)
V2=81 inches
</span><span>
5. The amount of wood that was left after the hole was cut out, is:
</span>
Vt=V1-V2
Vt=648 inches³