9514 1404 393
Answer:
k = 7
m = 8
Step-by-step explanation:
The diagonals bisect each other, so each half is equal to the opposite half.
k +4 = 11 . . . . down-sloping diagonal
k = 7
__
m = 8 . . . . up-sloping diagonal
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
379.94 rounded to the nearest tenth is = 379.9
Answer:
B.
Step-by-step explanation:
The correct option is B. Distributive property
Given,
On solving the above equation,
multiplying both sides by 3 we, get

now subtracting 21 from both the sides,

dividing both the sides by 2 we get,

Since in the above steps we follow all the giving property except the distributive property.
Hence the correct option is B. Distributive property.
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