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3 years ago

Find the HCF of the following by

Mathematics

1 answer:

Delicious77 [7]3 years ago

7 0

Answer:

here

72, 54, 27 are divisible by 3, to check divisibility by 3 we have to add the digits.

dividing all three digits by 3 we get :

3 x 24 = 72

3 x 18 = 54

3 x 9 = 27

now we have 24, 18, 9

check divisibility by 2, but no, it is not possible. 2 is not divisible by 5 so we take 3, yes three is divisible

24, 18, 9

3 x 8 = 24

3 x 6 = 18

3 x 3 = 9

so now we have 8,6,3

this is neither divisible by 2 or 3 so now we multiply 3 x 3

= 9

second answer is 4

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Step-by-step explanation:

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A length is measured at 21 cm correct to two significant figures, what is the lower bound of the length and upper bound?

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Answer:

20.5 and 21.5

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

3 years ago