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Ymorist [56]
2 years ago
15

help me on these 5 math problems, answer them correctly and explain your answers, please and thank you! <3 i have trouble on

these so please help.

Mathematics
2 answers:
sladkih [1.3K]2 years ago
7 0
The answer is H for this problem
BARSIC [14]2 years ago
6 0

Answer: H

Step-by-step explanation: move the dilations

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Step-by-step explanation:

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Which table shows a proportional relationship between x and y? x 2 3 5 6 y 3 4 7 9 x 4 6 8 10 y 6 8 10 12 x 1 5 8 10 y 15 75 120
AysviL [449]

Answer:

Only the 3rd table shows a proportional relation between x and y.

Step-by-step explanation:

The first table is  

x 2 3 5 6  

y 3 4 7 9

Here y is not increasing in uniform rate with x. So, the relation is not proportional.

The second table is  

x 4 6 8 10  

y 6 8 10 12

Here y is increasing in uniform rate with x, but at x = 0, y ≠ 0, Hence, the relationship is not proportional.

The third table is  

x 1 5 8 10  

y 15 75 120 150

Here, y is increasing in uniform rate with x, and  at x = 0, y = 0, Hence, the relationship is proportional.

The fourth table shows

x 3 9 10 15  

y 1 3 4 5

Here also y is not increasing in uniform rate with x. So, the relation is not proportional.

Therefore, only the 3rd table shows a proportional relation between x and y. (Answer)

5 0
3 years ago
Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units
Yakvenalex [24]

Answer:

a) positive direction: t < 2s & t>6s   ; negative direction: 2s < t < 6s

b) 7 m

c) 71 m

Step-by-step explanation:

Given:

v(t) = 3t^2 -24t +36   [0 , 7]

Find:

a) The value of time when particle is moving in positive direction:

The change in direction of the particle can be determined by v(t) > 0

Hence,

                                    0 < 3t^2 -24t +36

                                    0 < t^2 - 8t + 12

                                    0 < (t - 2)*(t - 6)

                                    t < 2s  , t  > 6s  

The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.

b) The displacement ds over the given interval [ 0 , 7 ]

                                  ds = integral (v(t)).dt

                                  ds = t^3 -12t^2 +36t

                                  ds = 7^3 -12*7^2 +36*7

                                  ds = 7 m

c) Total distance traveled in the interval:

                                 Total distance= ds(0-2) + ds(2-6) + ds(6-7)

                                 D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7

                                 D = 2*32 - 2*0 + 7

                                 D = 71 m          

     

6 0
3 years ago
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