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zhannawk [14.2K]
3 years ago
6

Y - 15 = 3x -2x + 5y = -3

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0
3x-y=-15 and 2x-5y-3=0
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BRIANLIST ANSWER!! Please help on this one question ( if you’re good at this) thanks :))
ivann1987 [24]

Answer:

Step-by-step explanation:

(21²+10²)½ = 23.25= 23.3

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3 years ago
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
4 years ago
A circular swimming pool has a radius of 15 ft. There is a path all around that pool that is three feet wide.
Romashka-Z-Leto [24]

Answer:

Circumference(C) of the circle is given by:

C = 2 \pi r

where, r is the radius of the circle.

As per the statement:

A circular swimming pool has a radius of 15 ft.

⇒radius of the pool(r) = 15 ft

There is a path all around that pool that is three feet wide.

⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft

Substitute these in the formula we have;

C = 2 \pi r'

⇒C = 2 \cdot 3.14 \cdot 18 = 113.04 ft

Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft

6 0
4 years ago
Read 2 more answers
How do you find the answer
KengaRu [80]
You need to measure the angles wich means that u use a protractor if the angle is 90 degrees is a straight angle if it is below 90 degrees is acute and if it is above 90 degrees it's obtuse

6 0
3 years ago
Multiply: (3x – 5)(–x + 4)
LiRa [457]

Answer:

Step-by-step explanation:

(3x – 5)(–x + 4)

(3x)(–x) + (3x)(4) + (–5)(–x) + (–5)(4).

-3x^2+12x +5x -20

-3x^2+ 17x -20

4 0
3 years ago
Read 2 more answers
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