I have seen this question before and I think you meant 10 more dimes than nickels.
We can use substitution to answer this question. The value of a nickel is 5 cents, and we can use the variable n to represent the number of nickels. The value of a dime is 10 cents, and we can use the variable d to represent the number of dimes.
First lets figure out the equations.
.10d+.5n=2.80 (the number of nickels (n) multiplied by .5 will tell us their money value. Same thing for the dimes)
d-n=10 (since there are 13 more dimes than nickels, the number of dimes value (d) minus the number of nickels value (n) will give us 10)
Now lets isolate a variable in one of the equations, preferably the second one because it doesn't have any visible coefficients,
d-n=10
-n=10-d (subtracted the d from both sides)
n=-10+d (made the n positive)
Now that we have the value of n, we can plug it into the other equation.
.10d+.05n=2.80
.10d+.05(-10+d)=2.80 (we replaced the n with the value that we previously got)
.10d-.5+.05d=2.80 (did the multiplication)
.15d-.5=2.80 (combined like terms)
.15d=3.30 (added the .5 to both sides)
d=22 (divided both sides by the .15)
Now that we know that there are 22 dimes and we also know that there are 10 less nickels than dimes, so we can subtract 10 from 22 to get the number of nickels. 22-10=12
d=22
n=12
When a number is next to a variable multiply so you problem really is 2(?)=60
-3x+13=16
Move +13 to the other side. Sign changes from +13 to -13.
-3x+13-13=16-13
-3x=16-13
-3x=3
Divide by -3 for both sides.
-3/-3x=3/-3
Cross out -3 and -3, divide by -3, then becomes 1*1*x=x
x=-1
Answer: x=-1
Answer:
Multiply it by itself one time.
Step-by-step explanation:
For example, if you are trying to find 3 squared, you would do 3*3.
If it's 3 cubed, you do 3*3*3
And so on and so forth
9514 1404 393
Answer:
- 6x +y = -6
- 6x -y = 8
- 5x +y = 13
Step-by-step explanation:
To rewrite these equations from point-slope form to standard form, you can do the following:
- eliminate parentheses
- subtract the x-term
- subtract the constant on the left
- if the coefficient of x is negative, multiply by -1
Of course, any operation you do must be done <em>to both sides of the equation</em>.
__
1. y -6 = -6(x +2)
y -6 = -6x -12 . . . . . eliminate parentheses
6x +y -6 = -12 . . . . . add 6x
6x +y = -6 . . . . . . . . add 6
__
2. y +2 = 6(x -1)
y +2 = 6x -6
-6x +y +2 = -6
-6x +y = -8
6x -y = 8 . . . . . . . . multiply by -1
__
3. y -3 = -5(x -2)
y -3 = -5x +10
5x +y -3 = 10
5x +y = 13
_____
<em>Additional comment</em>
The "standard form" of a linear equation is ax+by=c for integers a, b, c. The leading coefficient (generally, 'a') should be positive, and all coefficients should be mutually prime (have no common factors). That is why we multiply by -1 in problem 2.
