Answer: Yes, because 3502.86 is multiplied by the exponent. i think, because i was stuck between that and the other yes, and the other yes was wrong, so im pretty sure its that.
Tell me if im right.
Step-by-step explanation:
Answer:
1.25b when b < 12 , 1b & then 0.75 b when b <u>> </u>12
Step-by-step explanation:
- Price for b bagels = Price x Quantity
* Less than 12 bagels bought, cost $1.25 per bagel
So, price for b bagels, when (b < 12) = 1.25b
* 12 or more than 12 bagels bought, cost $1 upto first 12 bagels & 0.75b on each additional bagel
So, price for b bagels, when (b = 12) = b
So, price for b bagels, when (b > 12) = b + 0.75b' , where b' denotes extra b beyond 12
Answer:
x=-7, y= -20
Step-by-step explanation:
2x - y =6
x - y = 13
when I subract (x-y =13 ) from (2x-y =6)
2x -y =6
-x +y=-13
______________
x = -7
substitute x=-7 in the second equation
-7 - y =13
-y = 13 +7
-Y = 20
Y=-20
x=-7, y= -20
You need to solve 5 equations
1. 7x - 2.1 = 14.1
2. 7x - 2.1 = 30.9 and so on
1. 7x - 2.1 = 14.1
7x = 16.2
x = 2.314 so first number in the domain is 2.314
You can calculate the other 4 in the same way
Answer:
a) 0.96
b) 0.016
c) 0.018
d) 0.982
e) x = 2
Step-by-step explanation:
We are given with the Probability density function f(x)= 2/x^3 where x > 1.
<em>Firstly we will calculate the general probability that of P(a < X < b) </em>
P(a < X < b) = 
= 
= ![2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx](https://tex.z-dn.net/?f=2%5B%20%5Cfrac%7Bx%5E%7B-3%2B1%7D%20%7D%7B-3%2B1%7D%5D%5E%7Bb%7D_a%20%20%20dx)
{ Because ![\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a](https://tex.z-dn.net/?f=%5Cint_%7Ba%7D%5E%7Bb%7D%20x%5E%7Bn%7D%20dx%20%3D%20%5B%20%5Cfrac%7Bx%5E%7Bn%2B1%7D%20%7D%7Bn%2B1%7D%5D%5E%7Bb%7D_a)
}
= ![2[ \frac{x^{-2} }{-2}]^{b}_a](https://tex.z-dn.net/?f=2%5B%20%5Cfrac%7Bx%5E%7B-2%7D%20%7D%7B-2%7D%5D%5E%7Bb%7D_a)
= ![\frac{2}{-2} [ x^{-2} ]^{b}_a](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B-2%7D%20%5B%20x%5E%7B-2%7D%20%5D%5E%7Bb%7D_a)
= ![-1 [ b^{-2} - a^{-2} ]](https://tex.z-dn.net/?f=-1%20%5B%20b%5E%7B-2%7D%20-%20a%5E%7B-2%7D%20%20%5D)
= 
a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }
Comparing with general probability we get,
P(1 < X < 5) = 
= 
= 0.96 .
b) P(X > 8) = P(8 < X < ∞) = 1/
- 1/∞ = 1/64 - 0 = 0.016
c) P(6 < X < 10) = 
= 
= 0.018 .
d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)
= 
+ (1/
- 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982
e) We have to find x such that P(X < x) = 0.75 ;
⇒ P(1 < X < x) = 0.75
⇒ 
= 0.75
⇒ 
= 1 - 0.75 = 0.25
⇒ 
= 
⇒ = 4 ⇒ x = 
Therefore, value of x such that P(X < x) = 0.75 is 2.
