Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
4 Triangles 1/2(6)6()= 18 18x4= 72
5 squares 3X3=9. 5x9= 45
72+45= 117 sq in
D.) Nanometer is the smallest among your options.
It is equal to 10^-9
Hope this helps!
Answer:
599/711
Step-by-step explanation:
Band Sports Debate Total
Male 105 320 7 432
Female 105 160 14 279
Total 210 480 21 711
P(female or plays sports)
We want the probability that they are female or play sports, but we cannot double count the female sports players, so we subtract them
P(female) + P (sports) - (female and sports)
female/total + sports/total - female sports/ total
279/711 + 480/711 - 160/711
599/711
Answer:
the answer is in the picture below
Step-by-step explanation:
