Lead (IV) nitrate + sodium sulfate lead(IV) sulfate + sodium nitrate
Pb(NO3)4 (aq) + 2 Na2SO4 (aq) Pb(SO4)2 (s) + 4 NaNO3 (aq)
I think this is what you are looking for. If not I am sorry.
Answer:
In numerical order left to right, they are arranged by the number of protons in the nucleus of a single atom of each element
Answer: The final temperature (T) will be;
16.23°c
Explanation: To find the final temperature of any mixture of substance with an initial temperature use the formula;
M1c(T-T1) + M2c(T-T2)=0
c is the specific heat capacity of the two different substance, but because ice and water are the same, we assume c to be 1
T= final temperature of the mixture
T1= initial temperature of the ice= -10.2°c
T2= initial temperature of the water= 19.7°c
M1= mass of ice= 33.1g
M2= mass of water= 251g
Using the formula above
33.1(T-(-10.2)) + 251(T-19.7)=0
Solving out the bracket
33.1T + 337.62 + 251T - 4944.7 = 0
Collecting like terms to both side of the equation and solving
33.1T + 251T = 4944.7 - 33.62
284.1T = 4607.08
T = 4607.08÷284.1 = 16.23°c
1.706515172 ×10 to the power of 23
Answer:
A. Mass
Explanation:
Mass because ,mass is not a reliable measurement unlike the other ones.
