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Ksju [112]
4 years ago
13

Which describes a chemical properties

Chemistry
1 answer:
guajiro [1.7K]4 years ago
7 0
This is based off the protons in the Periodic Table. but if it is a compound then it is from the reactions from contributors. 
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What happens when light passes through a solution? perform an activity with a homogenous to expalin what happen when light pass
Brilliant_brown [7]

Answer:

light bends and makes effects in the water

Explanation:

6 0
3 years ago
2) Nitrogen gas will react with hydrogen gas to produce ammonia, NH3, How many
Delicious77 [7]

Answer:

12 grams of hydrogen gas

and 56 grams of nitrogen gas

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to  

17g/mol

68g

​

=4moles

4 moles of ammonia will be obtained from  

2

4×1

​

=2  moles of nitrogen and  

2

4×3

​

=6  moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56  grams.

6 moles of hydrogen corresponds to 6×2=12  grams.

5 0
3 years ago
Which statement is true about the cells of non-living objects? A. They have prokaryotic cells. B. They have eukaryotic cells. C.
zloy xaker [14]
D, obviously. All living things are made of one or more cells, therefore non-living things aren’t made of cells
8 0
3 years ago
If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?
lara31 [8.8K]

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

3 0
3 years ago
So I saw this question: If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + Na
Nataly_w [17]

mass of PbI₂ = 27.6606 g

<h3>Further explanation</h3>

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

4 0
3 years ago
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