Answer:
Step-by-step explanation:
Please refer to the attached figure for the labeling and construction in the given figure:
Given that minor angle of arc AB is .
Or in other words, we can say that angle subtended on the center O by the arc is .
Now, PA and PB are the tangents so, if we join the center of circle O with A and B, the angles formed are right angles.
i.e.
Now, we know that sum of internal angles of a quadrilateral is equal to .
Here, we have the quadrilateral AOPB.
Hence, the correct answer is:
