check the picture below.
namely, which of those intervals has the steepest slope, recall slope = average rate of change.
now, from the picture, notice, those two there are the steepest, the other three are leaning too much to the "ground".
so, from those two, which is the steepest anyway? let's check their slope.
![\bf \stackrel{\textit{from the 6th to the 8th hour}}{(\stackrel{x_1}{6}~,~\stackrel{y_1}{104})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{146})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{146-104}{8-2}\implies \cfrac{42}{2}\implies 21~~\bigotimes \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bfrom%20the%206th%20to%20the%208th%20hour%7D%7D%7B%28%5Cstackrel%7Bx_1%7D%7B6%7D~%2C~%5Cstackrel%7By_1%7D%7B104%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B8%7D~%2C~%5Cstackrel%7By_2%7D%7B146%7D%29%7D%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B146-104%7D%7B8-2%7D%5Cimplies%20%5Ccfrac%7B42%7D%7B2%7D%5Cimplies%2021~~%5Cbigotimes%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Answer:
Lateral Surface Area = 472 m²
Total Surface Area = 486m²
Step-by-step explanation:
The above prism is a Triangular prism
a) Lateral Surface Area = Perimeter of the Base × H
H = 29m
Perimeter of the Base = (7m + 7.28m + 2m)
= 16.28m
Lateral Surface Area = 16.28m × 29m
= 472.12 m²
Approximately to the nearest whole number = 472 m²
b) Total Surface Area
Triangular prism =
2 Triangles and 3 Rectangles
1st Triangle = 1/2 × base × Height
= 1/2 × 2m × 7m
= 7m²
2nd Triangle = 1/2 × base × height
= 1/2 × 2m × 7m
= 7m²
1st Rectangle = Length × Width
= 29m × 2m = 58m²
2nd Rectangle =
Length × Width
= 29m × 7.28m = 211.12m²
Length × Width
= 29m × 7m = 203m²
Total surface area = 7m² + 7m² + 58m² + 211.12m² + 203m²
= 486.12m²
Approximately to the nearest whole number = 486 m²
Option A is the correct option
Answer:
x = 4 ; y = 8
Step-by-step explanation:
we can use a system of two equation
x+1 = y-3
y-5 = 2x-5
we can find x in the first equation
x = y -4
we can now substitute x with this value in the second equation
y-5 = 2(y-4)-5
y = 2y-8
y = 8
we can now find x
x = 8-4 = 4
verify
2(4)-5 = 3
8-5 = 3
8-3 = 5
4 + 1 = 5
The process of finding which prime numbers you need to multiply together to get a certain number. ex: 21=7x3 20=2x2x5
