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Allisa [31]
2 years ago
9

A certain forest covers an area of 2100 km^2. Suppose that each year this area decreases by 5.25%. What will the area be after 6

years
Mathematics
1 answer:
Neko [114]2 years ago
4 0

Answer:

The area after 6 years is 1519.49km^2

<em></em>

Step-by-step explanation:

Given

a = 2100 --- Initial Value

r = 5.25\% --- Rate

Required

Determine the area after 6 years

Because the area reduces,, the following formula will be used to solve the question.

y = a*(1 - r)^t

Here

t = 6

So, we have:

y = 2100*(1 - 5.25\%)^6

Convert percentage to decimal

y = 2100*(1 - 0.0525)^6

y = 2100*(0.9475)^6

y = 1519.47866516

y = 1519.49 -- approximated

<em>The area after 6 years is </em>1519.49km^2<em></em>

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If x is equal to -6 which equality is true​
Papessa [141]

Answer:

-5 - 3x > 10

Step-by-step explanation:

x = -6

Plug in the x value for each inequality:

-5 - 3(-6) > 10

-5 + 18 > 10

13 > 10

True

-3 - 5(-6) < -14

-3 + 30 < -14

27 < -14

False

1 - 2(-6) > 13

1 + 12 > 13

13 > 13

False

2 - (-6) < -3

2 + 6 < -3

8 < -3

False

Only one of these is true; that is the answer.

8 0
3 years ago
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
3 years ago
Gabriele's Pie Shop sold 80 pies last month: 7/10 were apple pies and 1/10 were peach pies. How many pies were neither apple nor
AleksAgata [21]

Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

8/10, or 4/5 of the 80 apple pies were either apple or peach, which 4/5 of 80 is 64. The remaining pies will be neither apple nor peach. 80 - 64 = 16.

7 0
3 years ago
The diagram shows a right-angled triangle.
goldfiish [28.3K]

Answer:

Step-by-step explanation:

Ac²= AB²+ BC²

Ac²= 4²+15²= 16+225

Square both side

Ac = √241= 15.52cm

8 0
2 years ago
In a certain clothing store,6 shirts and 3 ties cost $79.50 ,and 3 shirts and 2 ties cost $41. determine the cost of each shirt.
Komok [63]

Answer:

Each shirt cost $12

Step-by-step explanation:

First, we have to interpret this question and turn each to an equation, letting shirts represent the letter s and ties represent the letter t.

6 shirts and 3 ties cost $79.50 would be interpreted to 6s+3t=79.5 ,and 3 shirts and 2 ties cost $41 would be interpreted to 3s+2t=41

Hence we have two equations, and we solve them simultaneously.

6s+3t=79.5 (Equation 1)

3s+2t=41 (Equation 2)

We can either use the substitution method or the elimination method but for the sake of this question, we use the Elimination method.

6s+3t=79.5 (Equation 1)

3s+2t=41 (Equation 2)

We multiply equation 1 by 2 and we multiply equation 2 by 3, I'm prefer to eliminate the

2(6s+3t=79.5)

12s+6t=159 Equation 3

3(3s+2t=41)

9s+6t=123 Equation 4

We subtract equation 4 from equation 3.

12s+6t=159

9s+6t=123

12s-9s=3s

6t-6t=0

159-123=36

We therefore have

3s=36

Divide both sides by 3

s=36/3

s=12

One shirt cost $12

3 0
3 years ago
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