Answer:
13,475
Step-by-step explanation:
First hour
350 people at $17.50 per ticket
350* $17.50 =$6125
Second hour
We add 20% more
350+350*.20 =350+70 =420
There were 420 people at $17.50
420*$17.50 =$7350
Add the total for the 2 hours
6125+7350=13,475
Let Susan's present age be x
Now, after 7 years ( her age will become 7 +x then) she'll be 2 as old she was 3 years ago.
Her age 3 years ago must be x-3
Now according to question,
twice Her age 3 years ago = her age after 7 years
now,
2(x-3) = 7+x
2x-6 = 7+x
2x-x =7+6
x = 13
x = 13
Therefore, her age presenr age is 13 years.
Answer:
z = 6
Step-by-step explanation:

Answer:
The population standard deviation is not known.
90% Confidence interval by T₁₀-distribution: (38.3, 53.7).
Step-by-step explanation:
The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus
.
Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,
- The area to the left of the lower end of the interval shall be
. - The area to the left of the upper end of the interval shall be
.
Look up the t-score of the upper end on an inverse t-table. Focus on the entry with
- a degree of freedom of 10, and
- a cumulative probability of 0.95.
.
This value can also be found with technology.
The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:
,
where
is the t-score at the upper end of the interval,
is the unbiased estimate for the standard deviation, and
is the sample size.
For this confidence interval:
Hence the width of the 90% confidence interval is
.
The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:
.